How do you expand #(3x+3y)^3#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer Ratnaker Mehta Aug 14, 2016 #27x^3+81x^2y+81xy^2+27y^3#. Explanation: We know that # : (a+b)^3=a^3+b^3+3ab(a+b)# Now, #(3x+3y)^3={3(x+y)}^3=3^3*(x+y)^3# #=27{x^3+y^3+3xy(x+y)}# #=27(x^3+y^3+3x^2y+3xy^2)# #=27x^3+81x^2y+81xy^2+27y^3#. Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 3187 views around the world You can reuse this answer Creative Commons License