How do you evaluate the limit $((x+5)^2-25)/x$ as x approaches $0$ ?

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Answer 1 · 2016-08-07T17:46:03

$10$ .

Reqd. Limit $=lim_(xrarr0){(x+5)^2-25}/x$

$=lim_(xrarr0){x^2+10x+25-25)/x$

$=lim_(xrarr0){cancelx(x+10)}/cancelx$

$=lim_(xrarr0)(x+10)$

$=10$ .

How do you evaluate the limit ((x+5)^2-25)/x((x+5)^2-25)/x as x approaches 00?