How do you evaluate the limit $(x^3+27)/(x+3)$ as x approaches $3$ ?

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Answer 1 · 2016-11-30T11:05:30

By substitution.

Because the limit of the denominator is not $0$ , we can use substitution to evaluate the limit.

$lim_(xrarr3) (x^3+27)/(x+3) = ((3^3)+27)/((3)+3) = 54/9 = 6$

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