How do you evaluate the limit #(x^2+4x+3)/(x+3)# as x approaches #-3#? Calculus Limits Determining Limits Algebraically 1 Answer Eddie Aug 11, 2016 #= -2# Explanation: #lim_{x to -3} (x^2+4x+3)/(x+3)# #= lim_{x to -3} ((x+3)(x+1))/(x+3)# let #y = x + 3# #= lim_{y to 0} y/y (y - 2)# #= -2# Answer link Related questions How do you find the limit #lim_(x->5)(x^2-6x+5)/(x^2-25)# ? How do you find the limit #lim_(x->3^+)|3-x|/(x^2-2x-3)# ? How do you find the limit #lim_(x->4)(x^3-64)/(x^2-8x+16)# ? How do you find the limit #lim_(x->2)(x^2+x-6)/(x-2)# ? How do you find the limit #lim_(x->-4)(x^2+5x+4)/(x^2+3x-4)# ? How do you find the limit #lim_(t->-3)(t^2-9)/(2t^2+7t+3)# ? How do you find the limit #lim_(h->0)((4+h)^2-16)/h# ? How do you find the limit #lim_(h->0)((2+h)^3-8)/h# ? How do you find the limit #lim_(x->9)(9-x)/(3-sqrt(x))# ? How do you find the limit #lim_(h->0)(sqrt(1+h)-1)/h# ? See all questions in Determining Limits Algebraically Impact of this question 11423 views around the world You can reuse this answer Creative Commons License