How do you evaluate the limit $(x^2-25)/(x+5)$ as x approaches $-5$ ?

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Answer 1 · 2016-08-15T02:53:07

$lim_(x ->-5)(x^2 - 25)/(x + 5) = -10$

Start by eliminating through factorization:

$=lim_(x -> -5)(cancel((x + 5))(x - 5))/cancel(x + 5)$

$= -5 - 5$

$=-10$

Hopefully this helps!

How do you evaluate the limit (x^2-25)/(x+5)(x^2-25)/(x+5) as x approaches -5-5?