How do you evaluate the limit #(1/(1+r)-1)/r# as r approaches #0#?

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Answer 1 · 2016-10-02T21:27:09

#(1/(1+r)-1)/r#

#=(1/(1+r)-(1+r)/(1+r))/r#

#=((1-(1+r))/(1+r))/r#

#=((1-1-r)/(1+r))/r#

#=(-r/(1+r))/r#

#=-r/(1+r)*1/r#

#=-1/(1+r)#

Now:

#lim_{r->0}-1/(1+r)=-1#