How do you evaluate the integral $int dx/e^(3x)$ ?

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Answer 1 · 2017-01-12T08:02:24

$=-1/3e^(-3x)+c$

You can rewrite the expression as:

$-1/3int-3e^(-3x)dx$

Then you can get:

$=-1/3e^(-3x)+c$

How do you evaluate the integral int dx/e^(3x)int dx/e^(3x)?