How do you evaluate the expression $log_11(11^(n-5))$ ?

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Answer 1 · 2016-10-17T14:55:00

The expression can be simplified to $n - 5$ .

Start by simplifying the expression using the rule $logn^a = alogn$ .

$=(n - 5)log_11(11)$

Now, simplify using the formula $log_a(n) = logn/loga$ .

$=(n - 5)log11/log11$

$=(n - 5)(1)$

$= n - 5$

Hopefully this helps!

How do you evaluate the expression log_11(11^(n-5))log_11(11^(n-5))?