How do you evaluate squareroot(5) - squareroot(2)? Algebra Radicals and Geometry Connections Addition and Subtraction of Radicals 1 Answer Meave60 Nov 7, 2015 #sqrt 5-sqrt 2=0.821854415127#. Explanation: #sqrt 5-sqrt 2# cannot be simplified further, as both #5# and #2# are prime numbers. However, you could use a calculator, in which case #sqrt 5-sqrt 2=0.821854415127#. Answer link Related questions How do you add and subtract radicals? How is a radical considered a "like term"? How do you simplify #4\sqrt{3}+2\sqrt{12}#? How do you add #3""^3sqrt(2)+5""^3sqrt(16)#? How do you subtract #\sqrt{8x^3}-4x\sqrt{98x}#? How do you combine the radical #\sqrt{6}-\sqrt{27}+2\sqrt{54}+3\sqrt{48}#? How do you simplify #""^3sqrt{\frac{16x^5}{135y^4}}#? What is #sqrt(50)-sqrt(18)#? How do you add #3sqrt2+4sqrt2#? What is the square root of 50 + the square root of 8? See all questions in Addition and Subtraction of Radicals Impact of this question 1815 views around the world You can reuse this answer Creative Commons License