How do you evaluate $sqrt(b^2-4ac)$ for a=-9, b=10, c=-1?

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Answer 1 · 2017-07-19T03:39:42

See a solution process below:

To evaluate this expression substitute:

$color(red)(-9)$ for $color(red)(a)$

$color(blue)(10)$ for $color(blue)(b)$

$color(green)(-1)$ for $color(green)(c)$

$sqrt(color(blue)(b)^2 - 4color(red)(a)color(green)(c))$ becomes:

$sqrt(color(blue)(10)^2 - (4 * color(red)(-9) * color(green)(-1))) =>$

$sqrt(100 - 36) =>$

$sqrt(64) =>$

$8$

How do you evaluate sqrt(b^2-4ac)sqrt(b^2-4ac) for a=-9, b=10, c=-1?