How do you evaluate #sec (40) * sin (50)#?

1 Answer

May 26, 2016

Explanation:

#P = sec (40)sin (50) = sin (50)/cos (40)#
Reminder of property of complementary arcs:
#cos (pi/2 - x) = sin x#
#cos (40) = cos (90 - 50) = sin (50)#
Therefor:
#P = sin (50)/sin (50) = 1#

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How do you evaluate #sec (40) * sin (50)#?

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