How do you evaluate sec(25pi/6)? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Alan P. Apr 19, 2016 sec(25pi/6)=2/sqrt(3) Explanation: (25pi)/6 = 2xx(2pi)+pi/6 Each 2pi represents one complete rotation about the origin. So color(white)("XXX")(25pi)/6=pi/6 By definition sec = "hypotenuse"/"adjacent" So sec((25pi)/6)=sec(pi/6)=2/sqrt(3) Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 6876 views around the world You can reuse this answer Creative Commons License