How do you evaluate $\sqrt[3]{2187} + 2 \sqrt[3]{3}$ $\root[ 3] { 2187} + 2\root [ 3] { 3}$ ?

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Answer 1 · 2017-07-04T16:47:05

$\sqrt[3]{2187} + 2 \sqrt[3]{3} = 11 \sqrt[3]{3}$ $root(3)2187+2root(3)3=11root(3)3$

$\sqrt[3]{2187} + 2 \sqrt[3]{3}$ $root(3)2187+2root(3)3$

= $\sqrt[3]{3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3} + 2 \sqrt[3]{3}$ $root(3)(3xx3xx3xx3xx3xx3xx3)+2root(3)3$ )

= $root(3)(ul(3xx3xx3)xxul(3xx3xx3)xx3)+2root(3)3$

= $3xx3xxroot(3)3+2root(3)3$

= $9root(3)3+2root(3)3$

= $11root(3)3$

How do you evaluate \root[ 3] { 2187} + 2\root [ 3] { 3}3√2187+23√3\root[ 3] { 2187} + 2\root [ 3] { 3}?