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How do you evaluate #log sqrt 0.0001#?

1 Answer

Oct 22, 2015

I found #-2# but I considered base #10# for your log.

Explanation:

I assume a log in base #10# so you have:
#log_(10)(sqrt(0.0001))=log_(10)(1/10000)^(1/2)=1/2[log_(10)(1)-log_(10)(10000)]=1/2[0-4]=-2#

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