How do you evaluate $log_9 (1/3)$ ?

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Answer 1 · 2016-08-31T00:16:02

$-1/2$

$log_9(1/3) = log_9 3^-1 = -log_9 3$

$= -log_9 9^(1/2)$

$= -1/2$

To check answer

$log_9 (1/3) = ln(1/3)/ln9$

$~= -1.09861/2.19723 ~=-1/2$

How do you evaluate log_9 (1/3)log_9 (1/3)?