How do you evaluate #log_7 (7^(2x))#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Shwetank Mauria Oct 18, 2016 #log_7(7^(2x))=2x# Explanation: As #log_a p^n=nlog_a p# and #log_a a=1# #log_7(7^(2x))# = #2xlog_7 7# = #2x xx1=2x# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 1894 views around the world You can reuse this answer Creative Commons License