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How do you evaluate $log_7 (7^(2x))$ ?

1 Answer

Shwetank Mauria

Oct 18, 2016

$log_7(7^(2x))=2x$

Explanation:

As $log_a p^n=nlog_a p$ and $log_a a=1$

$log_7(7^(2x))$

= $2xlog_7 7$

= $2x xx1=2x$

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