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How do you evaluate #log_7 7#?

1 Answer

Shwetank Mauria

Aug 12, 2016

#log_7(7)=1#

Explanation:

If #a^m=b# in exponential form, we can write it in logarithmic form as #log_ab=m#.

Let #log_7(7)=x# and writing it in exponential form, we get #7^x=7=7^1# or #x=1#

Note - In fact for all values of #a#, we have #log_aa=1#

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