How do you evaluate #log_7(343)#?

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Answer 1 · 2015-11-29T01:01:34

#log_7(343) = 3#

If #x=log_7(343)#
then we are looking for a value of #x# such that #7^x= 343#

#7^1=7#
#7^2=49#
#7^3=343#

#rArr x=3#

In most cases a question like this would require the use of a calculator. In this case the question was obviously set up for a direct solution.

Answer 2 · 2015-11-30T14:06:25

3

#log_7(343)=log_7(7^3)#
#=3log_7(7)#
#=3*1#
#=3#