How do you evaluate ${log}_{6} (1)$ $log_6(1)$ ?

Question

8950 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-23T08:47:38

${log}_{6} (1) = 0$ $log_6(1)=0$

We know that ${log}_{x} y = z \Leftrightarrow x^{z} = y$ $log_xy=z hArr x^z=y$

Bur for any number $x$ $x$ , we have $x^{0} = 1$ $x^0=1$ ,

and hence ${log}_{x} (1) = 0$ $log_x(1)=0$ and that is true for $x = 6$ $x=6$ too.

Hence ${log}_{6} (1) = 0$ $log_6(1)=0$ .

How do you evaluate log_6(1)log6(1)log_6(1)?