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How do you evaluate #log_6(1)#?

1 Answer

Shwetank Mauria

Mar 23, 2016

#log_6(1)=0#

Explanation:

We know that #log_xy=z hArr x^z=y#

Bur for any number #x#, we have #x^0=1#,

and hence #log_x(1)=0# and that is true for #x=6# too.

Hence #log_6(1)=0#.

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