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How do you evaluate #log_4 4^-0.38#?

1 Answer

Nov 30, 2016

I got #-0.38#

Explanation:

We can take the exponent in front of the log and write:

#-0.38log_4(4)=#

but #log_4(4)=1# (from the definition of log) so you get:

#-0.38*1=-0.38#

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