How do you evaluate ${log}_{4} 16 = x$ $log_4 16 =x$ ?

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Answer 1 · 2016-05-03T07:42:36

${log}_{4} (16) = 2$ $log_4(16) = 2$

We will use the following:

with those, we have

${log}_{4} (16) = {log}_{4} (4^{2})$ $log_4(16) = log_4(4^2)$

$= 2 {log}_{4} (4)$ $=2log_4(4)$

$= 2 (1)$ $=2(1)$

$= 2$ $=2$

How do you evaluate log_4 16 =xlog416=xlog_4 16 =x?