How do you evaluate $log_4 1/64$ ?

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Answer 1 · 2015-07-09T14:15:39

$log_b 1=0$ , for any base.

So we get $1/64$

Answer 2 · 2015-07-09T14:51:15

If the question was intended to be: Find $log_4(1/64)$ , then the answer is $-3$ .

Remember that the log base 4 of a number is the exponent needed on 4 to get that number.

$1/64 = 1/4^3 = 4^(-3)$

Now what exponent do I need to put on 4, in order to get $4^(-3)$ ?

(Yes, it is a self-answering question. It's fun to think of other self-answering questions. OK, it might be nerdy fun.)

$log_4 4^(-3) = -3$

How do you evaluate log_4 1/64log_4 1/64?