How do you evaluate $log_343 49$ ?

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Answer 1 · 2016-10-23T18:14:20

$log_343 49=2/3$

$"change the base 243 to base 7"$

$log_343 49=(log_7 49)/(log _7 343)=(log _7 7^2)/(log_7 7^3)=(2*log 7)/(3*log_7 7)$

$log _7 7=1$

$log_343 49=(2*1)/(3*1)$

$log_343 49=2/3$

How do you evaluate log_343 49log_343 49?