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How do you evaluate #log_343 3#?

1 Answer

Shwetank Mauria

Sep 17, 2016

#log_343 3=0.1882#

Explanation:

Let #log_343 3=x#

then #343^x=3#

or #log(343^x)=log3#

or #x xx log343=log3#

or #x=log3/log343=0.4771/2.5353=0.1882#

Hence, #log_343 3=0.1882#

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