How do you evaluate log 300 - log 3?

1 Answer
Gió
Nov 4, 2015

Have a look:

Explanation:

I would use the property of logs that tells us:
loga*b=loga+logb
To get:
log (3*100)-log(3)=
=log(3)+log(100)-log(3)=
=cancel(log3)+log(100)cancel(-log3)=
=log(100)
If the base of the log is 10 then:
log_(10)(100)=2

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