How do you evaluate $log 25 + 1/2log3$ ?

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Answer 1 · 2015-08-06T17:30:23

$log(25*sqrt(3))=1.64$ 2 d.p.

Using:

$loga+logb=logab$ and $bloga=loga^b$

=>

$log25+1/2log3=log(25*sqrt(3))=1.64$ 2 d.p.

How do you evaluate log 25 + 1/2log3 log 25 + 1/2log3?