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How do you evaluate $log_225 15$ ?

1 Answer

Aug 28, 2016

$1/2$ .

Explanation:

$x=log_(225) 15 rArr 225^x=15 rArr (15^2)^x=15rArr 15^(2x)=15^1$

#rArr 2x=1

$rArr x=1/2$

$rArr log_(225) 15=1/2$ .

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