How do you evaluate #log_2(1/8)#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Bdub Mar 3, 2016 #log_2(1/8)=log_2(1/2^3)=log_2 2^-3=-3log_2 2=-3# Explanation: Use the property #log_a a^x=x# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 12602 views around the world You can reuse this answer Creative Commons License