How do you evaluate log_14 (1/14)?

1 Answer
May 9, 2018

-1

Explanation:

"using the "color(blue)"law of logarithms"

•color(white)(x)log_b x=nhArrx=b^n

"let "log_(14)(1/14)=n

rArr1/14=14^n

rArr14^-1=14^nrArrn=-1