How do you evaluate log_14 (1/14)?
1 Answer
May 9, 2018
Explanation:
"using the "color(blue)"law of logarithms"
•color(white)(x)log_b x=nhArrx=b^n
"let "log_(14)(1/14)=n
rArr1/14=14^n
rArr14^-1=14^nrArrn=-1