How do you evaluate #log_(1/9) (1/81)#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Shwetank Mauria Nov 11, 2016 #log_(1/9)(1/81)=2# Explanation: As #(1/9)^2=1/81#, by the definition of logarithm that #if a^b=m#, then #log_a m=b#, we get #log_(1/9)(1/81)=2# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 3285 views around the world You can reuse this answer Creative Commons License