How do you evaluate $log_(1/5) 25$ ?

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Answer 1 · 2016-08-21T18:16:56

$log_(1/5)25=-2$

Let $log_(1/5)25=x$ , then

$(1/5)^x=25$ or

$1/5^x=5^2$ or

$5^(-x)=5^2$

i.e. $-x=2$ or

$x=-2$

Hence $log_(1/5)25=-2$ .

How do you evaluate log_(1/5) 25log_(1/5) 25?