How do you evaluate $log_(1/3) (1/27)$ ?

Question

5046 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-01T04:02:22

$3$

$log_(1/3)(1/27)$
$=log_(1/3)(1/3)^3$
$=3log_(1/3)(1/3)$
$=3$

Alternatively, you can do it this way :

Recall that $log_ab=c, =>a^c=b$

let $log_(1/3)(1/27)=x$
$=> (1/3)^x=1/27=(1/3)^3$
Hence, $x=3$

How do you evaluate log_(1/3) (1/27)log_(1/3) (1/27)?