How do you evaluate #log_(1/2) 32#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Cesareo R. Aug 29, 2016 #-5# Explanation: #log_(1/2) 32 = log_e 32/(log_e (1/2)) = log_e 2^5/(-log_e 2) = -5log_e 2/(log_e 2) = -5# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 4170 views around the world You can reuse this answer Creative Commons License