How do you evaluate log_(1/2) (1/64)? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Cesareo R. Aug 3, 2016 6 Explanation: log_(1/2) (1/64) = log_{1/2}(1/2)^6=6 because log_a a^b = b Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm log_(1/4) 1/64? How do I find the logarithm log_(2/3)(8/27)? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 4254 views around the world You can reuse this answer Creative Commons License