How do you evaluate #log 0.0001#?

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How do you evaluate #log 0.0001#?

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Answer 1 · 2015-10-29T12:38:35

#log(0.0001)=-4#

Explanation:

Recall that by the definition of logarithms:
#log_a(y)=x<=>y=a^x#
In this case:
#log(0.0001)=x#
#10^x = 0.0001=># but: #0.0001=10^-4# so:
#10^x=10^-4=>#same bases on each side of an equation must have the same exponents, thus:
#x=-4#

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How do you evaluate #log 0.0001#?

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