How do you evaluate $g(x)=log_ax$ for $x=a^2$ ?

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Answer 1 · 2018-05-31T14:36:03

$g(x)=2$

Inputting $a^2$ for $x$ , we get

$g(x)=log_a(a^2)$

At this point, the key realization here is that we can leverage the logarithm property

$log_a(a)=1$

$log_a$ and $a$ cancel each other out, so we essentially have

$g(x)=cancel(log_a)(cancela^2)$

$=>g(x)=2$

Hope this helps!

How do you evaluate g(x)=log_axg(x)=log_ax for x=a^2x=a^2?