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How do you evaluate #g(x)=lnx# for #x=e^3#?

1 Answer

Jan 8, 2017

#=>g(x)=ln(x)=3#

Explanation:

#ln(x)->ln(e^3)" "=" "3ln(e)#

But #ln(e)=1#

#ln(x)->ln(e^3)" "=" "3ln(e)" "=" "3xx1=3#

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