How do you evaluate $f(x)=3lnx$ for $x=0.75$ ?

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Answer 1 · 2018-05-30T12:13:01

$f(0.75) = -0.86 (2 dp)$

$f(x) = 3 ln x; x =0.75$

$f(0.75) = 3 ln 0.75;$ or

$f(0.75) = 3 * (-0.28768);$ or

$f(0.75) = -0.86 (2 dp)$ [Ans]

How do you evaluate f(x)=3lnxf(x)=3lnx for x=0.75x=0.75?