How do you evaluate #abs(-4)timesabs(-12)/3times-abs3/abs6#?

1 Answer
Jim G.
Nov 27, 2016

#-8#

Explanation:

The #color(blue)"absolute value function"# is always positive.

The reason being that it denotes the distance a value is from zero and distance is always positive.

#" Thus" |-4|=|4|=4# as 4 and - 4 are both 4 units from zero.

#rArr|-4|xx|-12|/3xx-|3|/|6|" can be expressed as"#

#4xx12/3xx-3/6#

#=4xx4xx-1/2=cancel(16)^8xx-1/cancel(2)^1=-8#

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