How do you evaluate $(abs(3-3)--4)times5$ ?

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Answer 1 · 2016-11-27T16:54:34

$20$

PEMDAS needed:

P: Parenthesis
E: Exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction

First solve what is in the parenthesis:

$( |0| + 4 ) xx 5 larr$ two minuses make a plus and the absolute value of $0$ is $0$

$=(0 + 4) xx 5$

$=(4) xx 5$

$=20$

How do you evaluate (abs(3-3)--4)times5(abs(3-3)--4)times5?