How do you evaluate $a b + | - 40 |$ $ab+abs(-40)$ when a=0, b=3?

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Answer 1 · 2018-03-06T02:17:28

The result is $40$ $40$ .

Plug in the numbers, multiply, then compute the absolute value:

$\Rightarrow a b + | - 40 |$ $color(white)=>ab+|-40|$

$\Rightarrow (0) (3) + | - 40 |$ $=>(0)(3)+|-40|$

$= 0 + | - 40 |$ $=0+|-40|$

$= | - 40 |$ $=|-40|$

$= 40$ $=40$

How do you evaluate ab+abs(-40)ab+|−40|ab+abs(-40) when a=0, b=3?