How do you evaluate $- 7 - (2^{4} \div 8)$ $-7-(2^4div8)$ ?

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Answer 1 · 2015-06-18T04:19:47

Use the order of operations represented by PEMDAS: parentheses, exponents, multiplication and division, addition and subtraction.

$- 7 - (2^{4} \div 8)$ $-7-(2^4-:8)$ =

Do the operations inside the parentheses first.

Raise $2$ $2$ to the power of $4$ $4$ .

$2^{4} = 16$ $2^4=16$

$- 7 - (16 \div 8)$ $-7-(16-:8)$ =

Next complete the division.

$16 \div 8 = 2$ $16-:8=2$

Finally subtract $2$ $2$ from $- 7$ $-7$ .

$- 7 - (2) = - 9$ $-7-(2)=-9$

$- 7 - (2^{4} \div 8) = - 9$ $-7-(2^4-:8)=-9$

How do you evaluate -7-(2^4div8)−7−(24÷8)-7-(2^4div8)?