How do you evaluate $(- 6- - 6) ^ { 3} + 4$ ?

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Answer 1 · 2017-10-17T01:02:17

$4$

Focus on the parenthesis first. We have

$-6--6$ which is simplified to $-6+6$ which is just $0$

So our expression is now

$(0)^3+4$

We now evaluate

$0^3+4$

$=0+4$

$=4$

Answer 2 · 2017-10-17T01:03:05

The answer is $4$ .

Begin by simplifying within the parentheses.

$(-6-(-6))^3+4 = 0^3+4$ because $-6-(-6)=-6+6=0$

$0^3=0$ , so $0^3+4 = 4$

The answer is $4$ .

How do you evaluate (- 6- - 6) ^ { 3} + 4(- 6- - 6) ^ { 3} + 4?