How do you evaluate $- 6 \cdot 3 + ∣ ∣ - 3 (- 4 + 2^{3}) ∣ ∣$ $-6*3+ abs(-3(-4+2^3))$ ?

Question

How do you evaluate $- 6 \cdot 3 + ∣ ∣ - 3 (- 4 + 2^{3}) ∣ ∣$ $-6*3+ abs(-3(-4+2^3))$ ?

1 Answer

Impact of this question

1886 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-05T21:41:20

Zero.

Explanation:

Start with the quantity inside the modulus:

$- 3 (- 4 + 2^{3})$ $-3 (-4 +2^3)$ = $- 3 (- 4 + 8) = - 24$ $-3 (-4 +8)= -24$
Take the bsolute value, i.e $24$ $24$ and substute in te oroginal equation.

$- 6 \cdot 3 + 24$ $-6*3 +24$ = $- 24 + 24$ $-24 +24$ = $0$ $0$

Science

Math

Humanities

... and beyond

How do you evaluate $- 6 \cdot 3 + ∣ ∣ - 3 (- 4 + 2^{3}) ∣ ∣$ $-6*3+ abs(-3(-4+2^3))$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you evaluate −6⋅3+∣∣−3(−4+23)∣∣-6*3+ abs(-3(-4+2^3))?

1 Answer

Explanation:

Related questions

Impact of this question

How do you evaluate $- 6 \cdot 3 + ∣ ∣ - 3 (- 4 + 2^{3}) ∣ ∣$ $-6*3+ abs(-3(-4+2^3))$ ?