How do you evaluate $5(3+12) + 42(23-4)$ ?

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Answer 1 · 2015-07-07T06:04:07

Distribute the $5$ and the $42$ . Add and subtract from left to right.

Distribute the $5$ and the $42$ .

Multiply $5$ times the terms in the first set of parentheses, and multiply $42$ times the terms in the second set of parentheses.

$5*3+5*12+42*23-42*4$ =

$15+60+966-168$ =

Add and subtract from left to right.

$1041-168=873$

Answer 2 · 2015-07-07T11:18:49

Rather than distributing to remove the parentheses, you could do the parentheses first, then multiply, then add.

$5(3+12) + 42(23-4)$

$= 5(15)+42(19)$

$= 75 + 798$

$= 873$

How do you evaluate 5(3+12) + 42(23-4) 5(3+12) + 42(23-4) ?