How do you evaluate $3 {log}_{2} 2 - {log}_{2} 4$ $3 log_2 2 - log_2 4$ ?

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How do you evaluate $3 {log}_{2} 2 - {log}_{2} 4$ $3 log_2 2 - log_2 4$ ?

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Answer 1 · 2015-05-01T15:44:32

In this way:

$3 {log}_{2} 2 - {log}_{2} 4 = 3 {log}_{2} 2 - {log}_{2} 2^{2} = 3 {log}_{2} 2 - 2 {log}_{2} 2 =$ $3log_2 2-log_2 4=3log_2 2-log_2 2^2=3log_2 2-2log_2 2=$

$= {log}_{2} 2$ $=log_2 2$ .

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How do you evaluate $3 {log}_{2} 2 - {log}_{2} 4$ $3 log_2 2 - log_2 4$ ?

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