How do you evaluate $2\times \{ 6+ [ 12\div ( 3+ 1) ] \} - 1$ ?

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Answer 1 · 2016-12-11T22:43:03

First work the parentheses from inside out. After that the multiplication and then the subtraction.

$=2xx{6+[12div4]}-1$
$=2xx{6+3}-1$
$=2xx9-1$
$=18-1$
$=17$

How do you evaluate 2\times \{ 6+ [ 12\div ( 3+ 1) ] \} - 12\times \{ 6+ [ 12\div ( 3+ 1) ] \} - 1?