How do you draw the line with the x intercept of -4 and y intercept of -1/2?

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How do you draw the line with the x intercept of -4 and y intercept of -1/2?

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Answer 1 · 2017-09-13T15:07:55

See a solution process below

Explanation:

The $x$ $x$ -intercept is the point on the $x$ $x$ -axis where the line crosses. Therefore, the $x$ $x$ value is $0$ $0$ . So, we can write the $x$ $x$ -intercept of $- 4$ $-4$ as: $(0, - 4)$ $(0, -4)$

Likewise, the $y$ $y$ -intercept is the point on the $y$ $y$ -axis where the line crosses. Therefore, the $y$ $y$ value is $0$ $0$ . So, we can write the $y$ $y$ -intercept of $- \frac{1}{2}$ $-1/2$ as: $(- \frac{1}{2}, 0)$ $(-1/2, 0)$

We can next graph the two points on the coordinate plane:

graph{(x^2+(y+4)^2-0.05)((x-0.5)^2+y^2-0.05)=0 [-15, 15, -7.5, 7.5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x^2+(y+4)^2-0.05)((x-0.5)^2+y^2-0.05)(-8x+y+4)=0 [-15, 15, -7.5, 7.5]}

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How do you draw the line with the x intercept of -4 and y intercept of -1/2?

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