How do you divide ( x^5 - x^3 - 3x^2 - 12x - 7 )/(x - 2 )x5x33x212x7x2?

1 Answer

(x^5-x^3-3x^2-12x-7)/(x-2)=x5x33x212x7x2=

x^4+2x^3+3x^2+3x-6+(-19)/(x-2)x4+2x3+3x2+3x6+19x2

Explanation:

First, arrange the dividend and divisor from highest to lowest degree of terms. The missing terms will have to be provided with a zero numerical coefficient.

the dividend:

x^5-x^3-3x^2-12x-7" "x5x33x212x7 should be

x^5+0*x^4-x^3-3x^2-12x-7x5+0x4x33x212x7

the divisor x-2x2 is already arranged

Let us divide

" " " " " " " "underline(" "x^4+2x^3+3x^2+3x-6 " " " " " " " " " " ")
x-2" "|~" "x^5+0*x^4-x^3-3x^2-12x-7
" " " " " " " "underline(" "x^5-2x^4"" " " " " " " " " " " " " " " " " " " " ")
" " " " " " " " " " " " " "2x^4-x^3-3x^2-12x-7
" " " " " " " " " " " " " "underline(2x^4-4x^3 " " " " " " " " " " " " " " " " ")
" " " " " " " " " " " " " " " " " "3x^3-3x^2-12x-7
" " " " " " " " " " " " " " " " " "underline(3x^3 -6x^2" " " " " " " " " " " " ")
"" " " " " " " " " " " " " " " " " " " " " " "3x^2-12x-7
" " " " " " " " " " " " " " " " " " " " " " underline(3x^2-6x" " " " " " " " " ")
"" " " " " " " " " " " " " " " " " " " " " " " " " " " "-6x-7
" " " " " " " " " " " " " " " " " " " " " " " " " " ""underline(-6x+12 " " " " ")
"" " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " "-19larrremainder

We write the answer in the form

("Dividend")/("divisor")="Quotient"+("Remainder")/("Divisor")

(x^5-x^3-3x^2-12x-7)/(x-2)=

x^4+2x^3+3x^2+3x-6+(-19)/(x-2)

God bless....I hope the explanation is useful.