How do you divide $\frac{x^{5} - 3 x^{3} + 3 x + 2}{(x^{2} - 1) (x + 2)}$ $(x^5-3x^3+ 3x +2)/((x^2-1)(x+2)$ ?

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Answer 1 · 2018-06-15T17:05:56

$x^{2} - 2 x + 2 + \frac{- 4 x^{2} + x + 6}{(x^{2} - 1) (x + 2)}$ $x^2 - 2x + 2 + frac{-4x^2 + x + 6}{(x^2 - 1)(x + 2)}$

The denominator is $x^{3} - x + 2 x^{2} - 2$ $x^3 - x + 2x^2 - 2$

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How do you divide (x^5-3x^3+ 3x +2)/((x^2-1)(x+2)x5−3x3+3x+2(x2−1)(x+2)(x^5-3x^3+ 3x +2)/((x^2-1)(x+2)?